Two 5 molal solutions are prepared by dissolving a non-electrolyte non-volatile solute separately in the solvents X and Y. The molecular weights of the solvents are M x and M y, respectively where M x = 3/4 My. The relative lowering of vapor pressure of the solution in X is ''m'' times that of the solution in Y. Given that the number of moles of solute is very small in comparison to that of the solvent, the value of ''m'' is:

Solutions: JEE Main 2018 Chemistry question

JEE Main 2018 · 15 Apr, Evening shift · Q2009

JEE Main 201815 Apr, Evening shiftChemistryHardSolutions71× since 2002

Two 5 molal solutions are prepared by dissolving a non-electrolyte non-volatile solute separately in the solvents X and Y. The molecular weights of the solvents are M_x and M_y, respectively where M_x =

{3 \over 4}

My. The relative lowering of vapor pressure of the solution in X is ''m'' times that of the solution in Y. Given that the number of moles of solute is very small in comparison to that of the solvent, the value of ''m'' is :

Solutions: JEE Main 2018 Chemistry question

JEE Main 2018 · 15 Apr, Evening shift · Q2009

JEE Main 201815 Apr, Evening shiftChemistryHardSolutions71× since 2002

{3 \over 4}

Solutions: JEE Main 2018 Chemistry question

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Solutions: JEE Main 2018 Chemistry question

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