Solutions — JEE Main 2026 · 2 Apr, Evening shift · Q55

Question

Solution A is prepared by dissolving 1 g of a protein (molar mass = 50000 g mol ⁻¹) in 0.5 L of water at 300 K. Its osmotic pressure is x bar. Solution B is made by dissolving 2 g of same protein in 1 L of water at 300 K. Osmotic pressure of solution B is y bar. Entire solution of A is mixed with entire solution of B at same temperature. The osmotic pressure of resultant solution is z bar. x, y and z respectively are: (R = 0.083 L bar mol ⁻¹ K ⁻¹)

Accepted Answer

(A) 9.96×10⁻⁴; 9.96×10⁻⁴; 9.96×10⁻⁴

Answer

(B) 9.96×10⁻⁴; 9.96×10⁻⁴; 19.92×10⁻⁴

Answer

(C) 4.98×10⁻⁴; 4.98×10⁻⁴; 9.96×10⁻⁴

Answer

(D) 4.98×10⁻⁴; 4.98×10⁻⁴; 4.98×10⁻⁴

Solutions: JEE Main 2026 Chemistry question

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Solutions: JEE Main 2026 Chemistry question

More on Solutions