JEE Main 202225 Jun, Evening shiftMathematicsEasyTrigonometry118× since 2002The value of tan−1(cos(15π4)−1sin(π4)){\tan ^{ - 1}}\left( {{{\cos \left( {{{15\pi } \over 4}} \right) - 1} \over {\sin \left( {{\pi \over 4}} \right)}}} \right)tan−1(sin(4π)cos(415π)−1) is equal to :AOption A. −π4- {\pi \over 4}−4πBOption B. −π8- {\pi \over 8}−8πCOption C. −5π12- {{5\pi } \over {12}}−125πDOption D. −4π9- {{4\pi } \over 9}−94πCheckSkip · show solution