JEE Main 2025April, Unspecified (session-level dataset)MathematicsMediumTrigonometry118× since 2002The number of solutions of the equation (4−3)sinx−23cos2x=−41+3,x∈[−2π,5π2](4-\sqrt{3})\sin x - 2\sqrt{3}\cos^2x = -\frac{4}{1+\sqrt{3}},\quad x\in[-2\pi,\tfrac{5\pi}{2}](4−3)sinx−23cos2x=−1+34,x∈[−2π,25π] is equal to:AOption A. 4BOption B. 3COption C. 6DOption D. 5CheckSkip · show solution
