JEE Main 201910 Jan, Evening shiftMathematicsMediumTrigonometry118× since 2002The value of cot(∑n=119cot−1(1+∑p=1n2p))\cot \left( {\sum\limits_{n = 1}^{19} {{{\cot }^{ - 1}}} \left( {1 + \sum\limits_{p = 1}^n {2p} } \right)} \right)cot(n=1∑19cot−1(1+p=1∑n2p)) is :AOption A. 2223{{22} \over {23}}2322BOption B. 2322{{23} \over {22}}2223COption C. 2119{{21} \over {19}}1921DOption D. 1921{{19} \over {21}}2119CheckSkip · show solution
