JEE Main 2003Annual, Paper 1MathematicsEasyTrigonometry118× since 2002The trigonometric equation sin−1x=2sin−1a{\sin ^{ - 1}}x = 2{\sin ^{ - 1}}asin−1x=2sin−1a has a solution for :AOption A. ∣a∣≥12\left| a \right| \ge {1 \over {\sqrt 2 }}∣a∣≥21BOption B. 12<∣a∣<12{1 \over 2} < \left| a \right| < {1 \over {\sqrt 2 }}21<∣a∣<21COption C. all real values of aaaDOption D. ∣a∣≤12\left| a \right| \le {1 \over {\sqrt 2 }}∣a∣≤21CheckSkip · show solution
