JEE Main 202429 Jan, Evening shiftMathematicsEasyTrigonometry118× since 2002The sum of the solutions x∈Rx \in \mathbb{R}x∈R of the equation 3cos2x+cos32xcos6x−sin6x=x3−x2+6\frac{3 \cos 2 x+\cos ^3 2 x}{\cos ^6 x-\sin ^6 x}=x^3-x^2+6cos6x−sin6x3cos2x+cos32x=x3−x2+6 isAOption A. 3BOption B. 1COption C. 0DOption D. −-−1CheckSkip · show solution
