JEE Main 202228 Jul, Evening shiftMathematicsMediumTrigonometry118× since 2002The sum of the absolute maximum and absolute minimum values of the function f(x)=tan−1(sinx−cosx)f(x)=\tan ^{-1}(\sin x-\cos x)f(x)=tan−1(sinx−cosx) in the interval [0,π][0, \pi][0,π] is :AOption A. 0BOption B. tan−1(12)−π4\tan ^{-1}\left(\frac{1}{\sqrt{2}}\right)-\frac{\pi}{4}tan−1(21)−4πCOption C. cos−1(13)−π4\cos ^{-1}\left(\frac{1}{\sqrt{3}}\right)-\frac{\pi}{4}cos−1(31)−4πDOption D. −π12\frac{-\pi}{12}12−πCheckSkip · show solution
