JEE Main 202329 Jan, Evening shiftMathematicsMediumTrigonometry118× since 2002The set of all values of λ\lambdaλ for which the equation cos22x−2sin4x−2cos2x=λ{\cos ^2}2x - 2{\sin ^4}x - 2{\cos ^2}x = \lambdacos22x−2sin4x−2cos2x=λ has a real solution xxx, is :AOption A. [−2,−1]\left[ { - 2, - 1} \right][−2,−1]BOption B. [−32,−1]\left[ { - {3 \over 2}, - 1} \right][−23,−1]COption C. [−2,−32]\left[ { - 2, - {3 \over 2}} \right][−2,−23]DOption D. [−1,−12]\left[ { - 1, - {1 \over 2}} \right][−1,−21]CheckSkip · show solution
