JEE Main 202431 Jan, Evening shiftMathematicsMediumTrigonometry118× since 2002The number of solutions, of the equation esinx−2e−sinx=2e^{\sin x}-2 e^{-\sin x}=2esinx−2e−sinx=2, is :AOption A. 0BOption B. 1COption C. 2DOption D. more than 2CheckSkip · show solution
