JEE Main 202120 Jul, Morning shiftMathematicsEasyTrigonometry118× since 2002The number of real roots of the equation tan−1x(x+1)+sin−1x2+x+1=π4{\tan ^{ - 1}}\sqrt {x(x + 1)} + {\sin ^{ - 1}}\sqrt {{x^2} + x + 1} = {\pi \over 4}tan−1x(x+1)+sin−1x2+x+1=4π is :AOption A. 1BOption B. 2COption C. 4DOption D. 0CheckSkip · show solution
