The molarity of the solution prepared by dissolving 6.3 g of oxalic acid (H₂C₂O₄.2H₂O) in 250 mL of water in mol L⁻¹ is x × 10⁻². The value of x is _ _ _ _ _ _ _. (Nearest integer) [Atomic mass: H: 1.0, C: 12.0, O: 16.0]

Some Basic Concepts in Chemistry: JEE Main 2021 Chemistry question

JEE Main 2021 · 31 Aug, Morning shift · Q18

JEE Main 202131 Aug, Morning shiftChemistryMediumSome Basic Concepts in Chemistry88× since 2002

The molarity of the solution prepared by dissolving 6.3 g of oxalic acid (H₂C₂O₄.2H₂O) in 250 mL of water in mol L^

-

1 is x

\times

10^

-

2. The value of x is _____________. (Nearest integer) [Atomic mass : H : 1.0, C : 12.0, O : 16.0]

Your answerType your answer. Integers and decimals are accepted.

JEE Main 2021 Some Basic Concepts in Chemistry Question with Answer (31 Aug Morning shift, Q18) | JEE Arc