The ratio of mass percentage (w/w) of C: H in a hydrocarbon is 12: 1. It has two carbon atoms. The weight (in g) of CO₂(g) formed when 3.38 g of this hydrocarbon is completely burnt in oxygen is: (Given: Molar mass in g mol ⁻¹ C: 12, H: 1, O: 16)

Some Basic Concepts in Chemistry: JEE Main 2026 Chemistry question

JEE Main 2026 · 2 Apr, Evening shift · Q51

JEE Main 20262 Apr, Evening shiftChemistryMediumSome Basic Concepts in Chemistry88× since 2002

The ratio of mass percentage (w/w) of C : H in a hydrocarbon is 12 : 1. It has two carbon atoms. The weight (in g) of

\mathrm{CO_2(g)}

formed when 3.38 g of this hydrocarbon is completely burnt in oxygen is : (Given : Molar mass in g mol

^{-1}

C : 12, H : 1, O : 16)

JEE Main 2026 Some Basic Concepts in Chemistry Question with Solution (2 Apr Evening shift, Q51) | JEE Arc

JEE Main 2026 · 2 Apr, Evening shift · Q51

JEE Main 20262 Apr, Evening shiftChemistryMediumSome Basic Concepts in Chemistry88× since 2002

The ratio of mass percentage (w/w) of C : H in a hydrocarbon is 12 : 1. It has two carbon atoms. The weight (in g) of

\mathrm{CO_2(g)}

formed when 3.38 g of this hydrocarbon is completely burnt in oxygen is : (Given : Molar mass in g mol

^{-1}

C : 12, H : 1, O : 16)