Electromagnetic Waves: JEE Main 2021 Physics question

The magnetic field vector of an electromagnetic wave is given by $B = {B_0}{{\widehat i + \widehat j} \over {\sqrt 2 }}\cos (kz - \omega t)$; where $\widehat i,\widehat j$ represents unit vector along x and y-axis respectively. At t = 0s, two electric charges q₁ of 4$\pi$ coulomb and q₂ of 2$\pi$ coulomb located at $\left( {0,0,{\pi \over k}} \right)$ and $\left( {0,0,{{3\pi } \over k}} \right)$, respectively, have the same velocity of 0.5 c $\widehat i$, (where c is the velocity of light). The ratio of the force acting on charge q₁ to q₂ is :-