JEE Main 20264 Apr, Evening shiftPhysicsEasyElectromagnetic Waves120× since 2002A magnetic field vector in an electromagnetic wave is represented by B⃗=B0sin(2πνt−2πxλ)j^\vec B=B_0\sin\left(2\pi\nu t-\frac{2\pi x}{\lambda}\right)\hat jB=B0sin(2πνt−λ2πx)j^. Its associated electric field vector is ______.AOption A. E⃗=−νλB0sin(2πνt−2πxλ)k^\vec E=-\nu\lambda B_0\sin\left(2\pi\nu t-\frac{2\pi x}{\lambda}\right)\hat kE=−νλB0sin(2πνt−λ2πx)k^BOption B. E⃗=−νλB0sin(2πνt−2πxλ)i^\vec E=-\nu\lambda B_0\sin\left(2\pi\nu t-\frac{2\pi x}{\lambda}\right)\hat iE=−νλB0sin(2πνt−λ2πx)i^COption C. E⃗=νλB0sin(2πνt−2πxλ)k^\vec E=\nu\lambda B_0\sin\left(2\pi\nu t-\frac{2\pi x}{\lambda}\right)\hat kE=νλB0sin(2πνt−λ2πx)k^DOption D. E⃗=νλB0sin(2πνt−2πxλ)i^\vec E=\nu\lambda B_0\sin\left(2\pi\nu t-\frac{2\pi x}{\lambda}\right)\hat iE=νλB0sin(2πνt−λ2πx)i^CheckSkip · show solution
