The magnetic field of a plane electromagnetic wave is B = 3 × 10⁻⁸ sin [ 200π (y + ct) ] i T where c = 3 × 10⁸ ms^–1 is the speed of light. The corresponding electric field is:

(B) E = - 9 sin [ 200π (y + ct) ] k V/m

(A) E = - 10⁻⁶ sin [ 200π (y + ct) ] k V/m

(C) E = 9 sin [ 200π (y + ct) ] k V/m

(D) E = 3 × 10⁻⁸ sin [ 200π (y + ct) ] k

Electromagnetic Waves: JEE Main 2020 Physics question

JEE Main 2020 · 3 Sep, Morning shift · Q6764

JEE Main 20203 Sep, Morning shiftPhysicsMediumElectromagnetic Waves120× since 2002

The magnetic field of a plane electromagnetic wave is

\overrightarrow B = 3 \times {10^{ - 8}}\sin \left[ {200\pi \left( {y + ct} \right)} \right]\widehat i

T where c = 3

\times

10⁸ ms^–1 is the speed of light. The corresponding electric field is :

JEE Main 2020 Electromagnetic Waves Question with Solution (3 Sep Morning shift, Q6764) | JEE Arc

JEE Main 2020 · 3 Sep, Morning shift · Q6764

JEE Main 20203 Sep, Morning shiftPhysicsMediumElectromagnetic Waves120× since 2002

The magnetic field of a plane electromagnetic wave is

\overrightarrow B = 3 \times {10^{ - 8}}\sin \left[ {200\pi \left( {y + ct} \right)} \right]\widehat i

T where c = 3

\times

10⁸ ms^–1 is the speed of light. The corresponding electric field is :