The magnetic field of a plane electromagnetic wave is given by: B = B₀ i[ cos (kz - ω t) ] + B i j cos (kz + ω t) B₀ = 3 × 10^–5 T and B1 = 2 × 10^–6 T. The rms value of the force experienced by a stationary charge Q = 10^–4 C at z = 0 is closest to:

Electromagnetic Waves: JEE Main 2019 Physics question

JEE Main 2019 · 9 Apr, Morning shift · Q6749

JEE Main 20199 Apr, Morning shiftPhysicsMediumElectromagnetic Waves120× since 2002

The magnetic field of a plane electromagnetic wave is given by :

\overline B = {B_0}\widehat i\left[ {\cos (kz - \omega t)} \right] + {B_i}\widehat j\cos (kz + \omega t)

B₀ = 3 × 10^–5 T and B1 = 2 × 10^–6 T. The rms value of the force experienced by a stationary charge Q = 10^–4 C at z = 0 is closest to :

JEE Main 2019 Electromagnetic Waves Question with Solution (9 Apr Morning shift, Q6749) | JEE Arc

JEE Main 2019 · 9 Apr, Morning shift · Q6749

JEE Main 20199 Apr, Morning shiftPhysicsMediumElectromagnetic Waves120× since 2002

The magnetic field of a plane electromagnetic wave is given by :

\overline B = {B_0}\widehat i\left[ {\cos (kz - \omega t)} \right] + {B_i}\widehat j\cos (kz + \omega t)

B₀ = 3 × 10^–5 T and B1 = 2 × 10^–6 T. The rms value of the force experienced by a stationary charge Q = 10^–4 C at z = 0 is closest to :