Electromagnetic Waves: JEE Main 2020 Physics question

The electric field of a plane electromagnetic wave is given by $\overrightarrow E = {E_0}{{\widehat i + \widehat j} \over {\sqrt 2 }}\cos \left( {kz + \omega t} \right)$ At t = 0, a positively charged particle is at the point (x, y, z) = $\left( {0,0,{\pi \over k}} \right)$. If its instantaneous velocity at (t = 0) is ${v_0}\widehat k$ , the force acting on it due to the wave is :