JEE Main 20244 Apr, Morning shiftPhysicsHardElectromagnetic Waves120× since 2002The electric field in an electromagnetic wave is given by E→=i^40cosω(t−z/c)NC−1\overrightarrow{\mathrm{E}}=\hat{i} 40 \cos \omega(\mathrm{t}-z / \mathrm{c}) \mathrm{NC}^{-1}E=i^40cosω(t−z/c)NC−1. The magnetic field induction of this wave is (in SI unit) :AOption A. B→=j^40ccosω(t−z/c)\overrightarrow{\mathrm{B}}=\hat{j} \frac{40}{\mathrm{c}} \cos \omega(\mathrm{t}-z / \mathrm{c})B=j^c40cosω(t−z/c)BOption B. B→=i^40ccosω(t−z/c)\overrightarrow{\mathrm{B}}=\hat{i} \frac{40}{\mathrm{c}} \cos \omega(\mathrm{t}-z / \mathrm{c})B=i^c40cosω(t−z/c)COption C. B⃗=j^40cosω(t−z/c)\vec{B}=\hat{j} 40 \cos \omega(t-z / c)B=j^40cosω(t−z/c)DOption D. B→=k^40ccosω(t−z/c)\overrightarrow{\mathrm{B}}=\hat{k} \frac{40}{\mathrm{c}} \cos \omega(\mathrm{t}-z / \mathrm{c})B=k^c40cosω(t−z/c)CheckSkip · show solution
