JEE Main 202227 Jul, Evening shiftMathematicsMediumTrigonometry118× since 2002The domain of the function f(x)=sin−1[2x2−3]+log2(log12(x2−5x+5))f(x)=\sin ^{-1}\left[2 x^{2}-3\right]+\log _{2}\left(\log _{\frac{1}{2}}\left(x^{2}-5 x+5\right)\right)f(x)=sin−1[2x2−3]+log2(log21(x2−5x+5)), where [t] is the greatest integer function, is :AOption A. (−52,5−52)\left(-\sqrt{\frac{5}{2}}, \frac{5-\sqrt{5}}{2}\right)(−25,25−5)BOption B. (5−52,5+52)\left(\frac{5-\sqrt{5}}{2}, \frac{5+\sqrt{5}}{2}\right)(25−5,25+5)COption C. (1,5−52)\left(1, \frac{5-\sqrt{5}}{2}\right)(1,25−5)DOption D. [1,5+52)\left[1, \frac{5+\sqrt{5}}{2}\right)[1,25+5)CheckSkip · show solution
