JEE Main 202229 Jun, Morning shiftMathematicsMediumTrigonometry118× since 2002The domain of the function cos−1(2sin−1(14x2−1)π){\cos ^{ - 1}}\left( {{{2{{\sin }^{ - 1}}\left( {{1 \over {4{x^2} - 1}}} \right)} \over \pi }} \right)cos−1(π2sin−1(4x2−11)) is :AOption A. R−{−12,12}R - \left\{ { - {1 \over 2},{1 \over 2}} \right\}R−{−21,21}BOption B. (−∞,−1]∪[1,∞)∪{0}( - \infty , - 1] \cup [1,\infty ) \cup \{ 0\}(−∞,−1]∪[1,∞)∪{0}COption C. (−∞,−12)∪(12,∞)∪{0}\left( { - \infty ,{{ - 1} \over 2}} \right) \cup \left( {{1 \over 2},\infty } \right) \cup \{ 0\}(−∞,2−1)∪(21,∞)∪{0}DOption D. (−∞,−12]∪[12,∞)∪{0}\left( { - \infty ,{{ - 1} \over {\sqrt 2 }}} \right] \cup \left[ {{1 \over {\sqrt 2 }},\infty } \right) \cup \{ 0\}(−∞,2−1]∪[21,∞)∪{0}CheckSkip · show solution
