JEE Main 2011Annual, Paper 1ChemistryMediumSolutions71× since 2002The degree of dissociation (α\alphaα ) of a weak electrolyte, A_xB_y is related to van’t Hoff factor (i) by the expression :AOption A. α=i−1x+y+1\alpha = {{i - 1} \over {x + y + 1}}α=x+y+1i−1BOption B. α=x+y−1i−1\alpha = {{x + y - 1} \over {i - 1}}α=i−1x+y−1COption C. α=x+y+1i−1\alpha = {{x + y + 1} \over {i - 1}}α=i−1x+y+1DOption D. α=i−1(x+y−1)\alpha = {{i - 1} \over {(x + y - 1)}}α=(x+y−1)i−1CheckSkip · show solution
