Electronic Devices: JEE Main 2014 Physics question

JEE Main 2014 · Session, Shift 1 · Q6863

JEE Main 2014Session, Shift 1PhysicsMediumElectronic Devices66× since 2002

The current voltage relation of diode is given by

{\rm I} = \left( {{e^{100V/T}} - 1} \right)mA,

where the applied voltage

V

is in volts and the temperature

T

is in degree kelvin. If a student makes an error measuring

\pm 0.01\,V

while measuring the current of

5

mA

300

K,

what will be the error in the value of current on

mA

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JEE Main 2014 Electronic Devices Question with Solution (Session Shift 1, Q6863) | JEE Arc