JEE Main 202622 Jan, Evening shiftPhysicsEasyElectronic Devices66× since 2002The correct truth table for the given input data of the following logic gate is :AOption A. Rows (A,B,C,D)→Y(A,B,C,D)\to Y(A,B,C,D)→Y: (1,1,0,1)→1(1,1,0,1)\to1(1,1,0,1)→1; (0,0,1,1)→0(0,0,1,1)\to0(0,0,1,1)→0; (1,0,1,0)→1(1,0,1,0)\to1(1,0,1,0)→1; (1,1,1,1)→0(1,1,1,1)\to0(1,1,1,1)→0BOption B. Rows (A,B,C,D)→Y(A,B,C,D)\to Y(A,B,C,D)→Y: (1,1,0,1)→0(1,1,0,1)\to0(1,1,0,1)→0; (0,0,1,1)→1(0,0,1,1)\to1(0,0,1,1)→1; (1,0,1,0)→1(1,0,1,0)\to1(1,0,1,0)→1; (1,1,1,1)→1(1,1,1,1)\to1(1,1,1,1)→1COption C. Rows (A,B,C,D)→Y(A,B,C,D)\to Y(A,B,C,D)→Y: (1,1,0,1)→1(1,1,0,1)\to1(1,1,0,1)→1; (0,0,1,1)→0(0,0,1,1)\to0(0,0,1,1)→0; (1,0,1,0)→0(1,0,1,0)\to0(1,0,1,0)→0; (1,1,1,1)→1(1,1,1,1)\to1(1,1,1,1)→1DOption D. Rows (A,B,C,D)→Y(A,B,C,D)\to Y(A,B,C,D)→Y: (1,1,0,1)→0(1,1,0,1)\to0(1,1,0,1)→0; (0,0,1,1)→0(0,0,1,1)\to0(0,0,1,1)→0; (1,0,1,0)→1(1,0,1,0)\to1(1,0,1,0)→1; (1,1,1,1)→1(1,1,1,1)\to1(1,1,1,1)→1CheckStep-by-step hintSkip · show solution