JEE Main 202226 Jul, Morning shiftMathematicsMediumTrigonometry118× since 2002tan(2tan−115+sec−152+2tan−118)\tan \left(2 \tan ^{-1} \frac{1}{5}+\sec ^{-1} \frac{\sqrt{5}}{2}+2 \tan ^{-1} \frac{1}{8}\right)tan(2tan−151+sec−125+2tan−181) is equal to :AOption A. 1BOption B. 2COption C. 14\frac{1}{4}41DOption D. 54\frac{5}{4}45CheckSkip · show solution