JEE Main 202227 Jun, Morning shiftMathematicsEasyTrigonometry118× since 2002sin1(sin2π3)+cos−1(cos7π6)+tan−1(tan3π4){\sin ^1}\left( {\sin {{2\pi } \over 3}} \right) + {\cos ^{ - 1}}\left( {\cos {{7\pi } \over 6}} \right) + {\tan ^{ - 1}}\left( {\tan {{3\pi } \over 4}} \right)sin1(sin32π)+cos−1(cos67π)+tan−1(tan43π) is equal to :AOption A. 11π12{{11\pi } \over {12}}1211πBOption B. 17π12{{17\pi } \over {12}}1217πCOption C. 31π12{{31\pi } \over {12}}1231πDOption D. −-−3π4{{3\pi } \over {4}}43πCheckSkip · show solution
