JEE Main 2025January, Unspecified (session-level dataset)MathematicsMediumIntegral Calculus369× since 2002Let f(x)=7tan8x+7tan8x−3tan4x−3tan2xf(x) = 7 \tan^8 x + 7 \tan^8 x - 3 \tan^4 x - 3 \tan^2 xf(x)=7tan8x+7tan8x−3tan4x−3tan2x, I1=∫0π/4f(x)dxI_1 = \int_0^{\pi/4} f(x) \mathrm{d}xI1=∫0π/4f(x)dx and I2=∫0π/4xf(x)dxI_2 = \int_0^{\pi/4} x f(x) \mathrm{d}xI2=∫0π/4xf(x)dx. Then 7I1+12I27 I_1 + 12 I_27I1+12I2 is equal to:AOption A. 2BOption B. 1COption C. 2π2\pi2πDOption D. π\piπCheckStep-by-step hintSkip · show solution
