JEE Main 20266 Apr, Evening shiftMathematicsEasyIntegral Calculus369× since 2002The value of the integral ∫−11(x3+∣x∣+1x2+2∣x∣+1)dx\displaystyle\int_{-1}^{1}\left(\frac{x^3+|x|+1}{x^2+2|x|+1}\right)dx∫−11(x2+2∣x∣+1x3+∣x∣+1)dx is equal to :AOption A. 3loge23\log_e23loge2BOption B. 2loge22\log_e22loge2COption C. 5loge35\log_e35loge3DOption D. 3loge33\log_e33loge3CheckSkip · show solution
