JEE Main 2025January, Unspecified (session-level dataset)MathematicsMediumDifferential Equations163× since 2002Let x=x(y)x = x(y)x=x(y) be the solution of the differential equation y2dx+(x−1y)dy=0y^2 \mathrm{d}x + \left(x - \frac{1}{y}\right) \mathrm{d}y = 0y2dx+(x−y1)dy=0. If x(1)=1x(1) = 1x(1)=1, then x(1y)x\left(\frac{1}{y}\right)x(y1) is:AOption A. 12+e\frac{1}{2} + e21+eBOption B. 3+e3 + e3+eCOption C. 3−e3 - e3−eDOption D. 32+e\frac{3}{2} + e23+eCheckStep-by-step hintSkip · show solution
