JEE Main 20265 Apr, Evening shiftMathematicsEasyDifferential Equations163× since 2002Let f:[1,∞)→Rf:[1,\infty)\to\mathbb{R}f:[1,∞)→R be a differentiable function defined as f(x)=∫1xf(t) dt+(1−x)(logex−1)+ef(x)=\int_1^x f(t)\,dt+(1-x)(\log_e x-1)+ef(x)=∫1xf(t)dt+(1−x)(logex−1)+e. Then the value of f(f(1))f(f(1))f(f(1)) is :AOption A. (1+ee)(1+e^e)(1+ee)BOption B. (1+e)(1+e)(1+e)COption C. (1+e+ee)(1+e+e^e)(1+e+ee)DOption D. 1+2e1+2e1+2eCheckSkip · show solution
