JEE Main 2025January, Unspecified (session-level dataset)MathematicsMediumIntegral Calculus369× since 2002The value of ∫e2e41x(e(logex)2+1e(logex)2+1)−1dx\int_{e^2}^{e^4} \frac{1}{x} \left( \frac{e^{\left(\log_e x\right)^2 + 1}}{e^{\left(\log_e x\right)^2 + 1}} \right)^{-1} dx∫e2e4x1(e(logex)2+1e(logex)2+1)−1dx isAOption A. 2BOption B. loge2\log_e 2loge2COption C. 1DOption D. e2e^2e2CheckStep-by-step hintSkip · show solution
