Trigonometry: JEE Main 2025 Mathematics question

JEE Main 2025 · April, Unspecified (session-level dataset) · Q138

JEE Main 2025April, Unspecified (session-level dataset)MathematicsMediumTrigonometry118× since 2002

Considering the principal values of the inverse trigonometric functions, \sin⁻¹\bigl(\tfrac{\sqrt{3}}{2}x + \tfrac{1}{2}\sqrt{1-x²}\bigr), -\tfrac{1}{2} < x < \tfrac{1}{\sqrt{2}}, is equal to:

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JEE Main 2025 Trigonometry Question with Solution (April Unspecified (session-level dataset), Q138) | JEE Arc