JEE Main 2025April, Unspecified (session-level dataset)MathematicsMediumIntegral Calculus369× since 2002Let f(x)+2f(1x)=x2+5f(x)+2f\bigl(\tfrac{1}{x}\bigr)=x^2+5f(x)+2f(x1)=x2+5 and 2g(x)−3g(1x)=x2g(x)-3g\bigl(\tfrac{1}{x}\bigr)=x2g(x)−3g(x1)=x, x>0x>0x>0. If α=∫12f(x) dx\alpha=\int_1^2 f(x)\,dxα=∫12f(x)dx and β=∫12g(x) dx\beta=\int_1^2 g(x)\,dxβ=∫12g(x)dx, then the value of 9α+β9\alpha+\beta9α+β is:AOption A. 1BOption B. 0COption C. 10DOption D. 11CheckStep-by-step hintSkip · show solution