Light wave travelling in air along x-direction is given by E y = 540 sin π × 10⁴(x - ct) V m⁻¹. Then, the peak value of magnetic field of wave will be (Given c = 3 × 10⁸ ms⁻¹)

Electromagnetic Waves: JEE Main 2022 Physics question

JEE Main 2022 · 25 Jul, Evening shift · Q6795

JEE Main 202225 Jul, Evening shiftPhysicsEasyElectromagnetic Waves120× since 2002

Light wave travelling in air along x-direction is given by

{E_y} = 540\sin \pi \times {10^4}(x - ct)\,V{m^{ - 1}}

. Then, the peak value of magnetic field of wave will be (Given c = 3

\times

10⁸ ms^

-

JEE Main 2022 · 25 Jul, Evening shift · Q6795

JEE Main 202225 Jul, Evening shiftPhysicsEasyElectromagnetic Waves120× since 2002

Light wave travelling in air along x-direction is given by

{E_y} = 540\sin \pi \times {10^4}(x - ct)\,V{m^{ - 1}}

. Then, the peak value of magnetic field of wave will be (Given c = 3

\times

10⁸ ms^

-