Let tan ⁻¹y = tan ⁻¹x + tan ⁻¹(2x/(1 - x²)), where | x | < 1/(3). Then a value of y is:

Trigonometry: JEE Main 2015 Mathematics question

JEE Main 2015 · Session, Shift 1 · Q4088

JEE Main 2015Session, Shift 1MathematicsMediumTrigonometry118× since 2002

Let

{\tan ^{ - 1}}y = {\tan ^{ - 1}}x + {\tan ^{ - 1}}\left( {{{2x} \over {1 - {x^2}}}} \right),

where

\left| x \right| < {1 \over {\sqrt 3 }}.

Then a value of

y

is :

JEE Main 2015 · Session, Shift 1 · Q4088

JEE Main 2015Session, Shift 1MathematicsMediumTrigonometry118× since 2002

Let

{\tan ^{ - 1}}y = {\tan ^{ - 1}}x + {\tan ^{ - 1}}\left( {{{2x} \over {1 - {x^2}}}} \right),

where

\left| x \right| < {1 \over {\sqrt 3 }}.

Then a value of

y

is :