JEE Main 202230 Jun, Morning shiftMathematicsMediumTrigonometry118× since 2002Let m and M respectively be the minimum and the maximum values of f(x)=sin−12x+sin2x+cos−12x+cos2x, x∈[0,π8]f(x) = {\sin ^{ - 1}}2x + \sin 2x + {\cos ^{ - 1}}2x + \cos 2x,\,x \in \left[ {0,{\pi \over 8}} \right]f(x)=sin−12x+sin2x+cos−12x+cos2x,x∈[0,8π]. Then m + M is equal to :AOption A. 1+2+π1 + \sqrt 2 + \pi1+2+πBOption B. (1+2)π\left( {1 + \sqrt 2 } \right)\pi(1+2)πCOption C. π+2\pi + \sqrt 2π+2DOption D. 1+π1 + \pi1+πCheckSkip · show solution