JEE Main 20262 Apr, Evening shiftMathematicsEasyTrigonometry118× since 2002Let P={θ∈[0,4π]:tan2θ≠1}P=\{\theta\in[0, 4\pi]: \tan^2\theta\ne1\}P={θ∈[0,4π]:tan2θ=1} and S={a∈Z:2(cos8θ−sin8θ)sec2θ=a2,θ∈P}S=\{a\in\mathbf{Z}: 2(\cos^8\theta-\sin^8\theta)\sec2\theta=a^2, \theta\in P\}S={a∈Z:2(cos8θ−sin8θ)sec2θ=a2,θ∈P}. Then n(S)n(S)n(S) is :AOption A. 0BOption B. 1COption C. 2DOption D. 3CheckSkip · show solution