JEE Main 202225 Jul, Evening shiftMathematicsMediumTrigonometry118× since 2002Let x=sin(2tan−1α)x = \sin (2{\tan ^{ - 1}}\alpha )x=sin(2tan−1α) and y=sin(12tan−143)y = \sin \left( {{1 \over 2}{{\tan }^{ - 1}}{4 \over 3}} \right)y=sin(21tan−134). If S={a∈R:y2=1−x}S = \{ a \in R:{y^2} = 1 - x\}S={a∈R:y2=1−x}, then ∑α∈S16α3\sum\limits_{\alpha \in S}^{} {16{\alpha ^3}}α∈S∑16α3 is equal to _______________.Your answerType your answer. Integers and decimals are accepted.CheckSkip · show solution
