JEE Main 202623 Jan, Evening shiftMathematicsMediumTrigonometry118× since 2002Let π2<θ<π\frac{\pi}{2}<\theta<\pi2π<θ<π and cotθ=−122\cot\theta=-\frac{1}{2\sqrt2}cotθ=−221. Then the value of sin(15θ2)(cos8θ+sin8θ)+cos(15θ2)(cos8θ−sin8θ)\sin\left(\frac{15\theta}{2}\right)(\cos8\theta+\sin8\theta)+\cos\left(\frac{15\theta}{2}\right)(\cos8\theta-\sin8\theta)sin(215θ)(cos8θ+sin8θ)+cos(215θ)(cos8θ−sin8θ) is equal toAOption A. 23\frac{\sqrt2}{\sqrt3}32BOption B. −23-\frac{\sqrt2}{\sqrt3}−32COption C. 2−13\frac{\sqrt2-1}{\sqrt3}32−1DOption D. 1−23\frac{1-\sqrt2}{\sqrt3}31−2CheckSkip · show solution
