JEE Main 20248 Apr, Evening shiftMathematicsHardTrigonometry118× since 2002If the value of 3cos36∘+5sin18∘5cos36∘−3sin18∘\frac{3 \cos 36^{\circ}+5 \sin 18^{\circ}}{5 \cos 36^{\circ}-3 \sin 18^{\circ}}5cos36∘−3sin18∘3cos36∘+5sin18∘ is a5−bc\frac{a \sqrt{5}-b}{c}ca5−b, where a,b,ca, b, ca,b,c are natural numbers and gcd(a,c)=1\operatorname{gcd}(a, c)=1gcd(a,c)=1, then a+b+ca+b+ca+b+c is equal to :AOption A. 54BOption B. 52COption C. 50DOption D. 40CheckSkip · show solution
