JEE Main 20244 Apr, Morning shiftMathematicsMediumTrigonometry118× since 2002If the domain of the function sin−1(3x−222x−19)+loge(3x2−8x+5x2−3x−10)\sin ^{-1}\left(\frac{3 x-22}{2 x-19}\right)+\log _{\mathrm{e}}\left(\frac{3 x^2-8 x+5}{x^2-3 x-10}\right)sin−1(2x−193x−22)+loge(x2−3x−103x2−8x+5) is (α,β](\alpha, \beta](α,β], then 3α+10β3 \alpha+10 \beta3α+10β is equal to:AOption A. 95BOption B. 100COption C. 97DOption D. 98CheckSkip · show solution
