JEE Main 20205 Sep, Morning shiftMathematicsMediumTrigonometry118× since 2002If S is the sum of the first 10 terms of the series tan−1(13)+tan−1(17)+tan−1(113)+tan−1(121)+....{\tan ^{ - 1}}\left( {{1 \over 3}} \right) + {\tan ^{ - 1}}\left( {{1 \over 7}} \right) + {\tan ^{ - 1}}\left( {{1 \over {13}}} \right) + {\tan ^{ - 1}}\left( {{1 \over {21}}} \right) + ....tan−1(31)+tan−1(71)+tan−1(131)+tan−1(211)+.... then tan(S) is equal to :AOption A. 1011{10 \over {11}}1110BOption B. 511{5 \over {11}}115COption C. -65{6 \over {5}}56DOption D. 56{5 \over {6}}65CheckSkip · show solution
