JEE Main 20205 Sep, Evening shiftMathematicsMediumTrigonometry118× since 2002If L = sin²(π16)\left( {{\pi \over {16}}} \right)(16π) - sin²(π8)\left( {{\pi \over {8}}} \right)(8π) and M = cos²(π16)\left( {{\pi \over {16}}} \right)(16π) - sin²(π8)\left( {{\pi \over {8}}} \right)(8π), then :AOption A. L = −122+12cosπ8- {1 \over {2\sqrt 2 }} + {1 \over 2}\cos {\pi \over 8}−221+21cos8πBOption B. M = 122+12cosπ8{1 \over {2\sqrt 2 }} + {1 \over 2}\cos {\pi \over 8}221+21cos8πCOption C. M = 142+14cosπ8{1 \over {4\sqrt 2 }} + {1 \over 4}\cos {\pi \over 8}421+41cos8πDOption D. L = 142−14cosπ8{1 \over {4\sqrt 2 }} - {1 \over 4}\cos {\pi \over 8}421−41cos8πCheckSkip · show solution
