JEE Main 202429 Jan, Morning shiftMathematicsEasyTrigonometry118× since 2002If α,−π2<α<π2\alpha,-\frac{\pi}{2}<\alpha<\frac{\pi}{2}α,−2π<α<2π is the solution of 4cosθ+5sinθ=14 \cos \theta+5 \sin \theta=14cosθ+5sinθ=1, then the value of tanα\tan \alphatanα isAOption A. 10−1012\frac{10-\sqrt{10}}{12}1210−10BOption B. 10−106\frac{\sqrt{10}-10}{6}610−10COption C. 10−1012\frac{\sqrt{10}-10}{12}1210−10DOption D. 10−106\frac{10-\sqrt{10}}{6}610−10CheckSkip · show solution
