If in a triangle ABC, AB = 5 units, B = cos ⁻¹(3/5) and radius of circumcircle of Δ ABC is 5 units, then the area (in sq. units) of Δ ABC is:

Properties of Triangle: JEE Main 2021 Mathematics question

JEE Main 2021 · 20 Jul, Morning shift · Q5042

JEE Main 202120 Jul, Morning shiftMathematicsMediumProperties of Triangle19× since 2002

If in a triangle ABC, AB = 5 units,

\angle B = {\cos ^{ - 1}}\left( {{3 \over 5}} \right)

and radius of circumcircle of

\Delta

ABC is 5 units, then the area (in sq. units) of

\Delta

ABC is :