A triangle ABC lying in the first quadrant has two vertices as A(1, 2) and B(3, 1). If BAC = 90^(o) and area (Δ ABC) = 5 5 s units, then the abscissa of the vertex C is:

Properties of Triangle: JEE Main 2020 Mathematics question

JEE Main 2020 · 4 Sep, Morning shift · Q5027

JEE Main 20204 Sep, Morning shiftMathematicsMediumProperties of Triangle19× since 2002

A triangle ABC lying in the first quadrant has two vertices as A(1, 2) and B(3, 1). If

\angle BAC = {90^o}

and area

\left( {\Delta ABC} \right) = 5\sqrt 5

s units, then the abscissa of the vertex C is :

JEE Main 2020 · 4 Sep, Morning shift · Q5027

JEE Main 20204 Sep, Morning shiftMathematicsMediumProperties of Triangle19× since 2002

A triangle ABC lying in the first quadrant has two vertices as A(1, 2) and B(3, 1). If

\angle BAC = {90^o}

and area

\left( {\Delta ABC} \right) = 5\sqrt 5

s units, then the abscissa of the vertex C is :