If Electric field intensity of a uniform plane electromagnetic wave is given as E = - 301.6 sin (kz - ω t) a x + 452.4 sin (kz - ω t) a y V/m. Then magnetic intensity 'H' of this wave in Am⁻¹ will be: [Given: Speed of light in vacuum c = 3 × 10⁸ ms⁻¹, Permeability of vacuum μ ₀ = 4π × 10⁻⁷ NA⁻²]

(C) - 0.8 sin (kz - ω t) a y - 1.2 sin (kz - ω t) a x

(A) + 0.8 sin (kz - ω t) a y + 0.8 sin (kz - ω t) a x

(B) + 1.0 × 10⁻⁶ sin (kz - ω t) a y + 1.5 × 10⁻⁶(kz - ω t) a x

(D) - 1.0 × 10⁻⁶ sin (kz - ω t) a y - 1.5 × 10⁻⁶ sin (kz - ω t) a x

Electromagnetic Waves: JEE Main 2022 Physics question

JEE Main 2022 · 26 Jun, Morning shift · Q6787

JEE Main 202226 Jun, Morning shiftPhysicsMediumElectromagnetic Waves120× since 2002

If Electric field intensity of a uniform plane electromagnetic wave is given as

E = - 301.6\sin (kz - \omega t){\widehat a_x} + 452.4\sin (kz - \omega t){\widehat a_y}{V \over m}

. Then magnetic intensity 'H' of this wave in Am^

-

1 will be : [Given : Speed of light in vacuum

c = 3 \times {10^8}

ms^

-

1, Permeability of vacuum

{\mu _0} = 4\pi \times {10^{ - 7}}

NA^

-

JEE Main 2022 Electromagnetic Waves Question with Solution (26 Jun Morning shift, Q6787) | JEE Arc