JEE Main 202124 Feb, Morning shiftMathematicsMediumTrigonometry118× since 2002If e(cos2x+cos4x+cos6x+...∞)loge2{e^{\left( {{{\cos }^2}x + {{\cos }^4}x + {{\cos }^6}x + ...\infty } \right){{\log }_e}2}}e(cos2x+cos4x+cos6x+...∞)loge2 satisfies the equation t² - 9t + 8 = 0, then the value of 2sinxsinx+3cosx(0<x<π2){{2\sin x} \over {\sin x + \sqrt 3 \cos x}}\left( {0 < x < {\pi \over 2}} \right)sinx+3cosx2sinx(0<x<2π) is :AOption A. 3\sqrt 33BOption B. 32{3 \over 2}23COption C. 23\sqrt 33DOption D. 12{1 \over 2}21CheckSkip · show solution