JEE Main 2006Annual, Paper 1MathematicsMediumTrigonometry118× since 2002If 0<x<π0 < x < \pi0<x<π and cosx+sinx=12,\cos x + \sin x = {1 \over 2},cosx+sinx=21, then tanx\tan xtanx is :AOption A. (1−7)4{{\left( {1 - \sqrt 7 } \right)} \over 4}4(1−7)BOption B. (4−7)3{{\left( {4 - \sqrt 7 } \right)} \over 3}3(4−7)COption C. −(4+7)3- {{\left( {4 + \sqrt 7 } \right)} \over 3}−3(4+7)DOption D. (1+7)4{{\left( {1 + \sqrt 7 } \right)} \over 4}4(1+7)CheckSkip · show solution
