JEE Main 20198 Apr, Morning shiftMathematicsMediumTrigonometry118× since 2002If α=cos−1(35)\alpha = {\cos ^{ - 1}}\left( {{3 \over 5}} \right)α=cos−1(53), β=tan−1(13)\beta = {\tan ^{ - 1}}\left( {{1 \over 3}} \right)β=tan−1(31) where 0<α,β<π20 < \alpha ,\beta < {\pi \over 2}0<α,β<2π , then α\alphaα - β\betaβ is equal to :AOption A. tan−1(914){\tan ^{ - 1}}\left( {{9 \over {14 }}} \right)tan−1(149)BOption B. sin−1(9510){\sin ^{ - 1}}\left( {{9 \over {5\sqrt {10} }}} \right)sin−1(5109)COption C. cos−1(9510){\cos ^{ - 1}}\left( {{9 \over {5\sqrt {10} }}} \right)cos−1(5109)DOption D. tan−1(9510){\tan ^{ - 1}}\left( {{9 \over {5\sqrt {10} }}} \right)tan−1(5109)CheckSkip · show solution
